I came up with this problem after looking at the original one from @five_triangles (Find the area of the trapezoid ABCD) That's a lot of fun but along the way while modelling the solution in geogebra I noticed AF is also on the diagonal of the trapezoid.

Note the 15-75-90 triangles at the bottom. Nowadays when I see them I also think of the following construction: http://mymathclub.blogspot.com/2015/07/sometimes-one-direction-is-lot-tricker.html

which allows one to find the ratio of the sides without trigonometry: 1 : \(2 - \sqrt{3}\) for the legs.

Bonus: Another problem with one of these in it: The \(2 - \sqrt{3}\) in the expression is a dead giveaway.

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