tag:blogger.com,1999:blog-4227811469912372962.post1699169413021626002..comments2017-02-17T18:26:40.880-08:00Comments on Running a Math Club: My Experiences: Geometry Diversion / corny geometry pun.Benjamin Leisnoreply@blogger.comBlogger4125tag:blogger.com,1999:blog-4227811469912372962.post-21888921581692779692015-12-23T16:15:05.932-08:002015-12-23T16:15:05.932-08:00Very pretty. On a more complex construction I'...Very pretty. On a more complex construction I'm always amazed by how many different ways there are to arrive at the same solution. This is why geometry is so interesting.Benjamin Leishttp://www.blogger.com/profile/10974191081762367425noreply@blogger.comtag:blogger.com,1999:blog-4227811469912372962.post-56617486292701853172015-12-23T15:43:44.811-08:002015-12-23T15:43:44.811-08:00Here is another approach and a critique, directed ...Here is another approach and a critique, directed not towards the blogger, but at the educational community at large: http://bit.ly/1Oj5QlVFive Triangleshttp://www.blogger.com/profile/12846752710456413605noreply@blogger.comtag:blogger.com,1999:blog-4227811469912372962.post-55998530698198854102015-12-23T10:48:15.983-08:002015-12-23T10:48:15.983-08:00Well once you can express all the lengths in terms...Well once you can express all the lengths in terms of x, my original approach is viable. I'd do the area of the trapezoid is equal to the 2 similar triangles plus the interior one.Benjamin Leishttp://www.blogger.com/profile/10974191081762367425noreply@blogger.comtag:blogger.com,1999:blog-4227811469912372962.post-46726718375421539662015-12-23T08:54:39.321-08:002015-12-23T08:54:39.321-08:00This is very nice (and the digits 3-6-5 is a coinc...This is very nice (and the digits 3-6-5 is a coincidence).<br /><br />Now to throw down the gauntlet: can it be solved without Pythagoreas' theorem?Five Triangleshttp://www.blogger.com/profile/12846752710456413605noreply@blogger.com